SOLUTION: find the vertex, focus, and directrix of the parabola and sketch its graph. the equation is {{{y^2-4y-4x=0}}}

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: find the vertex, focus, and directrix of the parabola and sketch its graph. the equation is {{{y^2-4y-4x=0}}}      Log On


   

Question 290386: find the vertex, focus, and directrix of the parabola and sketch its graph.
the equation is y%5E2-4y-4x=0
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
This parabola open to the right.
vertex -1,2
directrix x=-2
focus 0,2