SOLUTION: i'm doing SOH CAH TOA it uses sin, cos and tan my teacher trys to explain were everything goes but i just get confused. my question is how do you set it up? and when doing the equa

Algebra ->  Triangles -> SOLUTION: i'm doing SOH CAH TOA it uses sin, cos and tan my teacher trys to explain were everything goes but i just get confused. my question is how do you set it up? and when doing the equa      Log On


   

Question 290330: i'm doing SOH CAH TOA it uses sin, cos and tan my teacher trys to explain were everything goes but i just get confused. my question is how do you set it up? and when doing the equation how do you know when to put either the x over the number or the number over the x? for example: a ladder is leaning on a building the ladder is 18 ft from the building and the angle of the ladder from the ground is 22.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
i'm doing SOH CAH TOA it uses sin, cos and tan my teacher trys to explain were everything goes but i just get confused. my question is how do you set it up? and when doing the equation how do you know when to put either the x over the number or the number over the x? for example:
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A ladder is leaning on a building the ladder is 18 ft from the building and the angle of the ladder from the ground is 22.
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Draw the picture.
You have a right triangle:
ladder = hypotenuse = 18
angle at the ground is 22 degrees
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side "opposite" 22 degrees is the wall
side "adjacent" to 22 degrees is the base of the triangle.
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To find "opposite" use sin(22)
sin(22) = opposite/hypotenuse
opposite = (hypotenuse)*(sin(22))
opposite = 18*0.3746 = 6.74 ft
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To find adjacent use cos(22)
cos(22) = adjacent/hypotenuse
adjacent = (hypotenuse)*cos(22)
adjacent = 18*0.9272 = 16.69 ft
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Cheers,
Stan H.