SOLUTION: The population of mice in a particular area is growing exponentially. on January 1, there were 5o mice, and by June 1, there were 200 mice, write an exponential function of the f

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: The population of mice in a particular area is growing exponentially. on January 1, there were 5o mice, and by June 1, there were 200 mice, write an exponential function of the f      Log On


   



Question 290248: The population of mice in a particular area is growing exponentially. on January 1, there were 5o mice, and by June 1, there were 200 mice, write an exponential function of the form y = ab^x that could be used to model the mouse population y of the area.write the function in terms of x, the number of months since January.
Answer by stanbon(75887) About Me  (Show Source):
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The population of mice in a particular area is growing exponentially. on January 1, there were 5o mice, and by June 1, there were 200 mice, write an exponential function of the form y = ab^x that could be used to model the mouse population y of the area.write the function in terms of x, the number of months since January.
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You have two points: (0,50) and (5,200)
y = ab^x
Using (0,50) you get 50 = ab^(0)
So, a = 50
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Using (5,200) you get 200 = 50b^5
b^5 = 4
b = 4^(1/5)
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Equation:
y = 50*4^(t/5)
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Cheers,
Stan H.
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