SOLUTION: Suppose that the wrapper of a candy bar lists its weight as 8 ounces. The actual weights of individual candy bars naturally vary to some extent. Suppose that these actual weights v
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Question 289348: Suppose that the wrapper of a candy bar lists its weight as 8 ounces. The actual weights of individual candy bars naturally vary to some extent. Suppose that these actual weights vary according to a normal distribution wth mean 8.5 ounces and standard deviation .325 ounces
What proportion of he candy bars weigh less less than adverised 8 ounces?
If the manufacturer wants to decrease this proportion from a) by changing the man of its candy bar weigts, should it increase or decrease that mean?
If the manufacturer wants to decrease this proportion from a) by changing the standard deviation of its candy bar weight should it increase or decrease that standard deviation?
Not sure what I need to do ....Thank you for your help Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Suppose that the wrapper of a candy bar lists its weight as 8 ounces.
The actual weights of individual candy bars naturally vary to some extent. Suppose that these actual weights vary according to a normal distribution wth mean 8.5 ounces and standard deviation .325 ounces
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What proportion of the candy bars weigh less less than adverised 8 ounces?
Find the z-value of 8:
z(8) = (8-8.5)/0.325 = -1.5385
P(x < 8) = P(z < -1.5385) = 0.062 weigh less than then 8 ounces.
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If the manufacturer wants to decrease this proportion from a) by changing the mean of its candy bar weights, should it increase or decrease that mean?
Increase it.
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If the manufacturer wants to decrease this proportion from a) by changing the standard deviation of its candy bar weight should it increase or decrease that standard deviation?
Decrease it to pull the distribution close to the mean.
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Cheers,
Stan H.
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