SOLUTION: at 7:00 a.m joe starts jogging at 6 mi/h. at 7:30 ken starts off after him. how fast must ken run in order to overtake him at 7:30 a.m.?

Algebra ->  Finance -> SOLUTION: at 7:00 a.m joe starts jogging at 6 mi/h. at 7:30 ken starts off after him. how fast must ken run in order to overtake him at 7:30 a.m.?       Log On


   



Question 289228: at 7:00 a.m joe starts jogging at 6 mi/h. at 7:30 ken starts off after him. how fast must ken run in order to overtake him at 7:30 a.m.?

Found 2 solutions by richwmiller, ankor@dixie-net.com:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
sorry but you input both times for ken as 7:30 am

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
at 7:00 a.m joe starts jogging; at 6 mi/h. at 7:30 ken starts off after him.
how fast must ken run in order to overtake him at 7:30 a.m.?
:
Really now, does this make sense to you?
: