SOLUTION: the sum of three numbers is 18,if the largest number is twice the number of the smallest +1 and the other numbers is 3 times the largest what are the three numbers?
Algebra ->
Sequences-and-series
-> SOLUTION: the sum of three numbers is 18,if the largest number is twice the number of the smallest +1 and the other numbers is 3 times the largest what are the three numbers?
Log On
Question 289123: the sum of three numbers is 18,if the largest number is twice the number of the smallest +1 and the other numbers is 3 times the largest what are the three numbers? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! The sum of three numbers is 18.
x + y + z = 18
:
If the largest number is twice the number of the smallest +1,
z = 2x + 1
:
and the other numbers is 3 times the largest
y = 3z
:
Replace z with (2x+1)
y = 3(2x+1)
y = 6x + 3
:
In the sum equation, replace y and z
x + (6x+3) + (2x+1) = 18
9x + 4 = 18
9x = 18 - 4
9x = 14
x =
x = 1
:
y = 6x + 3
y = 6* + 3
y = + 3
y = 9 + 3
y = 12
:
z = 2x + 1
z = 2* + 1
z = + 1
z = 3 + 1
z = 4
:
:
Check solution in the sum equation
1 + 12 + 4 = 18
