SOLUTION: Missing ages. Molly’s age is twice Anita’s. If the sum of
the squares of their ages is 80, then what are their ages?
I started this problem and took 80 divided by two which gav
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-> SOLUTION: Missing ages. Molly’s age is twice Anita’s. If the sum of
the squares of their ages is 80, then what are their ages?
I started this problem and took 80 divided by two which gav
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Question 289102: Missing ages. Molly’s age is twice Anita’s. If the sum of
the squares of their ages is 80, then what are their ages?
I started this problem and took 80 divided by two which gave me 40, then this is where i got stuck. Am i doing this right ro do i need to go about it differently? Found 2 solutions by stanbon, Stitch:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Missing ages. Molly’s age is twice Anita’s. If the sum of
the squares of their ages is 80, then what are their ages?
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Equations:
m = 2a
m^2 + a^2 = 80
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Substitute for "m" and solve for "a":
(2a)^2 + a^2 = 80
4a^2 + a^2 = 80
5a^2 = 80
a^2 = 16
a = 4 (Anita's age)
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Since m = 2a, m = 8 (Molly's age)
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Cheers,
Stan H.
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You can put this solution on YOUR website! Since you are dealing with squared numbers, you can not simply divide 80 by 2
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Set-Up:
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Let Molly's age = A
Let Anita's age = B
Equation 1:
Equation 2:
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Solution:
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Substitute the 2B from equation 1 into equation 2 for A
Equation 2: Rewrite the equation Simplify Simplify Divide both sides by 5 Take the square root of both sides
Now plug 4 into equation 1 for B
Equation 1:
(
