SOLUTION: Mike has 19 coins (nickels, dimes, and quarters) in his piggy bank with a total value of $2.35. There are two more dimes than nickels. How many of each type of cion does mike have?
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Question 289014: Mike has 19 coins (nickels, dimes, and quarters) in his piggy bank with a total value of $2.35. There are two more dimes than nickels. How many of each type of cion does mike have?
Nickels=
Dimes=
Quarters= Found 2 solutions by nyc_function, Fombitz:Answer by nyc_function(2741) (Show Source):
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NYC Math Tutor
You can put this solution on YOUR website! N-number of nickels, worth 5 cents each
D-number of dimes, worth 10 cents each
Q-number of quarters, worth 25 cents each
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"Mike has 19 coins"
1.
.
.
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"a total value of $2.35 (235 cents)"
2.
.
.
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"two more dimes than nickels"
3.
Substitute eq. 3 into 1 and 2.
1.
We'll call this eq. 4.
4.
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.
.
2.
We'll call this eq. 5.
5.
Now use eq. 4, to get Q in terms of N and substitute into eq. 5.
4.
5.
Now work backwards,
And finally,
6 nickels, 8 dimes, and 5 quarters.
