SOLUTION: Which of these equations are equivalent to 16? 3[7x-4(x-3)]+1=16 A:9x-2=16 B:9x+37=16 C:17x-2=16 D:17x+13=16 I already know the answer, but how do I find out which one it i

Algebra ->  Inequalities -> SOLUTION: Which of these equations are equivalent to 16? 3[7x-4(x-3)]+1=16 A:9x-2=16 B:9x+37=16 C:17x-2=16 D:17x+13=16 I already know the answer, but how do I find out which one it i      Log On


   

Question 288885: Which of these equations are equivalent to 16?
3[7x-4(x-3)]+1=16
A:9x-2=16
B:9x+37=16
C:17x-2=16
D:17x+13=16
I already know the answer, but how do I find out which one it is? Can you show me please? The correct answer is B, Here is what I got so far.
3[7x-4(x-3)]+1 Rewrite problem.
3[7x-4x+12]+1 Distribute the -4
3[3x+12]+1 Combine like terms.
That's as far as I got, I do not know where to come from here. Thank you for your time to help me.
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
None of them has x=16
I really don't know what you want.
I certainly have no clue what you are doing here
3[7x-4(x-3)]+1=16
nor where you got it. But it looks like you may have combined a couple equations.