SOLUTION: Find the points of intersection, if any, of the graphs in the system. Give the solution of: 4x^2 - 56x + 9y^2 + 160 = 0 and 4x^2 + y^2 - 64 = 0. Please and thank you!
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-> SOLUTION: Find the points of intersection, if any, of the graphs in the system. Give the solution of: 4x^2 - 56x + 9y^2 + 160 = 0 and 4x^2 + y^2 - 64 = 0. Please and thank you!
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Question 288644: Find the points of intersection, if any, of the graphs in the system. Give the solution of: 4x^2 - 56x + 9y^2 + 160 = 0 and 4x^2 + y^2 - 64 = 0. Please and thank you! Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website! Hint: First solve for in to get . Next replace the term in the first equation with (since the two are equal) to get .
From there, you have a quadratic equation (after simplification) in which you can use the quadratic formula to solve for 'x'. Once you have your solution(s) in terms of 'x', use the solution(s) to find the solution(s) in terms of 'y'.
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