SOLUTION: a sample of 80 car owners revealed that 24 owned station wagons and 62 owned cars which are not station wagons find the number k of people who owned both a station wagon and some o

Algebra ->  Permutations -> SOLUTION: a sample of 80 car owners revealed that 24 owned station wagons and 62 owned cars which are not station wagons find the number k of people who owned both a station wagon and some o      Log On


   

Question 288567: a sample of 80 car owners revealed that 24 owned station wagons and 62 owned cars which are not station wagons find the number k of people who owned both a station wagon and some other car?
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
You have 80 car owners in total.
24 owned station wagons.
62 owned cars which are not station wagons.
How many owned both a station wagon and a car.

24 + 62 = 86.

There are 86 cars and only 80 owners.

Assuming a maximum of 2 cars per owner, then the number of people who owned a car and a station wagon would be 6 I think.

If we have 6 people owning a car and a station wagon, then we have:

24 - 6 = 18 owned a station wagon only.
62 - 6 = 56 owned a car only.
6 owned a car and a station wagon.

That's a total of 18 + 56 + 6 = 80 people who either owned a car or a station wagon or a car and a station wagon.

That's a total of (18 * 1) + (56 * 1) + (6 * 2) cars = 18 + 56 + 12 = a total of 86 cars.