Question 288320: I have been working on this math problem and i can't seem to figure it out. I was wondering if someone could help me? Please and Thank You! I would deeply appreciate it!
Angle RTS is a right angle; segement RT=8, RS=17, VT=12, and VS=9. What is the measure of angle V? Explain.
Found 2 solutions by stanbon, dabanfield:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Angle RTS is a right angle; segment RT=8, RS=17, VT=12, and VS=9. What is the measure of angle V? Explain.
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If you do not have the picture, draw it.
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Use Pythagoras to find TS = x
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17^2 = 8^2 + x^2
x^2 = 225
x = 15
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Use the Law of Cosines to find measure of angle V
cos(V) = (12^2+9^2-15^2)/(2*12*9)
cos(V) = 0/216 = 0
V = 90 degrees
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Cheers,
Stan H.
Answer by dabanfield(803) (Show Source):
You can put this solution on YOUR website! I have been working on this math problem and i can't seem to figure it out. I was wondering if someone could help me? Please and Thank You! I would deeply appreciate it!
Angle RTS is a right angle; segement RT=8, RS=17, VT=12, and VS=9. What is the measure of angle V? Explain.
0 solutions
Since RTS forms a right triangle, by the Pythagorean Theorem we know that
(TS)^2 + (RT)^2 = 17^2 or
(TS)^2 + 8^2 = 289
(TS)^2 = 289 - 64
(TS)^2 = 225
Notice that for triangle TVS:
(TV)^2 + (VS)^2 = 9^2 + 12^2 = 81 + 144 = 225 so we have:
(TV)^2 + (VS)^2 = (TS)^2
By the Pythagorean Theorem then we know that triangle TVS is a right triangle with right angle at V.
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