SOLUTION: The length of a rectangle is 2 inches less than 3 times the number of inches in its width. If the perimeter of the rectangle is 28 inches, what is the width and length of the recta
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Question 288278: The length of a rectangle is 2 inches less than 3 times the number of inches in its width. If the perimeter of the rectangle is 28 inches, what is the width and length of the rectangle? Answer by amnd(23) (Show Source):
You can put this solution on YOUR website! Consider L as its length, and W as its width.
L is 2 inches less than 3 times W. This means that 3W subtracted by 2 would yield L:
L = 3W - 2
3W - L = 2 ... (1)
The perimeter of a rectangle is twice its width summed with twice its length:
2w + 2L = 28
simplified, by dividing with 2:
W + L = 14 ... (2)
Add up Equations (1) and (2) (in which L will be eliminated, as -L + L = 0):
.
3W - L = 2
1W + L = 14
-------------- +
4W = 16 W = 4
.
Because W + L = 14, L = 14 - w = 14 - 4 -> L = 10
