SOLUTION: If the vertices of the right angle triamgle ABC are A(-1,2) B(3,8) C(5,-2) use coordinate geometry to prove that point M,the midpoint of the hypotenuse is equidistant from all thre

Algebra ->  Test -> SOLUTION: If the vertices of the right angle triamgle ABC are A(-1,2) B(3,8) C(5,-2) use coordinate geometry to prove that point M,the midpoint of the hypotenuse is equidistant from all thre      Log On


   



Question 288074: If the vertices of the right angle triamgle ABC are A(-1,2) B(3,8) C(5,-2) use coordinate geometry to prove that point M,the midpoint of the hypotenuse is equidistant from all three vertices of the triangle.
Answer by Alan3354(69443) About Me  (Show Source):
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If the vertices of the right angle triamgle ABC are A(-1,2) B(3,8) C(5,-2) use coordinate geometry to prove that point M,the midpoint of the hypotenuse is equidistant from all three vertices of the triangle.
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BC is the hypotenuse
Mx = (3+5)/2 = 4
My = (8-2)/2 = 3
Midpoint M (4,3)
M is equidistant from B and C by definition.
s%5E2+=+diffy%5E2+%2B+diffx%5E2
s%5E2+=+1+%2B+5%5E2+=+26
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Find the distance from M to A:
s%5E2+=+5%5E2+%2B+1+=+26
Same distance
QED