SOLUTION: A propane tank is in the form of a cylinder with two half-spheres, one on each end. The radius of the cylinder is the same as the radius of each half-sphere. What is the volume of

Algebra ->  Bodies-in-space -> SOLUTION: A propane tank is in the form of a cylinder with two half-spheres, one on each end. The radius of the cylinder is the same as the radius of each half-sphere. What is the volume of       Log On


   



Question 288020: A propane tank is in the form of a cylinder with two half-spheres, one on each end. The radius of the cylinder is the same as the radius of each half-sphere. What is the volume of a propane tank of cylindrical length 12 ft and radius 5 ft, correct to the nearest whole cubic foot?

Found 2 solutions by nerdybill, Alan3354:
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
A propane tank is in the form of a cylinder with two half-spheres, one on each end. The radius of the cylinder is the same as the radius of each half-sphere. What is the volume of a propane tank of cylindrical length 12 ft and radius 5 ft, correct to the nearest whole cubic foot?
.
Volume of the two ends:
(4/3)(pi)r^3
=(4/3)(3.14)5^3
= 523.333 cubic feet
.
Volume of center section:
(1/2)(pi)r^2 * length
= (1/2)(3.14)5^2 * 12
= 471 cubic feet
.
Total:
523.333 + 471 = 994.333 cubic feet
Nearest whole cubic foot:
994 cubic feet

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
A propane tank is in the form of a cylinder with two half-spheres, one on each end. The radius of the cylinder is the same as the radius of each half-sphere. What is the volume of a propane tank of cylindrical length 12 ft and radius 5 ft, correct to the nearest whole cubic foot?
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Volume of the sphere is
%284%2F3%29%28pi%29r%5E3
= %284%2F3%29%283.14%295%5E3
= 523.33 cubic feet
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Volume of the cylindrical section is
pi%2Ar%5E2+%2A+length
= %283.14%295%5E2+%2A+12
= 942.478 cubic feet
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Total = 523.33 + 942.78
=~ 1466 cubic feet