SOLUTION: A man has $2.46 in pennies, nickels, dimes and quarters. If he has an equal number of coins of each kind, then the total number of coins he has is: (a) 4 (b) 6 (c) 24 (d) 36 (e)

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: A man has $2.46 in pennies, nickels, dimes and quarters. If he has an equal number of coins of each kind, then the total number of coins he has is: (a) 4 (b) 6 (c) 24 (d) 36 (e)      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 287624: A man has $2.46 in pennies, nickels, dimes and quarters. If he has an equal number of coins of each kind, then the total number of coins he has is:
(a) 4 (b) 6 (c) 24 (d) 36 (e) None of the above

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
We know that the total of one of each is .25+.10+.05+.01=.41 and that 2.46/.41=6
So he has 6*4=24 coins