SOLUTION: The sum of three numbers is 14. The sum of twice the first number, is 6 times the second number, and 7 times the third number is 77. The difference between 3 times the first number
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Question 287562: The sum of three numbers is 14. The sum of twice the first number, is 6 times the second number, and 7 times the third number is 77. The difference between 3 times the first number and the second number is 11. Find the three numbers. Found 2 solutions by Grinnell, richwmiller:Answer by Grinnell(63) (Show Source):
You can put this solution on YOUR website! PLease word this problem more correctly. It is poorly worded.
Must have clarification before proceeding further.
You can put this solution on YOUR website! a+b+c=14
so far so good
but you didn't copy all of it .
2a+?????=6b
7*c=77 ???
3a-b=11
Something is wrong with this sentence.
"The sum of twice the first number, is 6 times the second number, and 7 times the third number is 77."
if 7c=77 then c=11
and a +b=3
so b=1 or b=2
and a=1 or a=2
but that doesn't fit with 3a-b=11
So something is very wrong
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