SOLUTION: This is a two-part problem.
For {{{ f(x) = sqrt ( 1-2x ) }}} {{{ g(x) = -x+3 }}}
A) Find (FºG)(x)
B) Find the domain of (FºG)(x)
What I have so far, which I am not to
Algebra ->
Rational-functions
-> SOLUTION: This is a two-part problem.
For {{{ f(x) = sqrt ( 1-2x ) }}} {{{ g(x) = -x+3 }}}
A) Find (FºG)(x)
B) Find the domain of (FºG)(x)
What I have so far, which I am not to
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Question 287328: This is a two-part problem.
For
A) Find (FºG)(x)
B) Find the domain of (FºG)(x)
What I have so far, which I am not totally sure about it:
(FºG)(x) = simplified into
Is that correct for step A)? And how do I find the domain for step B)? Answer by jsmallt9(3758) (Show Source):
For the domain, you just have to find the set of acceptable values for x. The function you found in part A has the x inside a square root. Since we must have a non-negative (zero or positive) number inside the square root, the only values we can allow x to be are those those that make 2x-5 non-negative. In other "words"
Solving this:
This describes the acceptable values of x. This is the domain.
(