Question 28704: 1. when gary and rowena were married, rowena was two years younger than gary. how old was gary on his wedding day if sisteen years before his wedding he was twice as old as rowena was then?
2.rex is 30 years younger than his father. His mother is three times as old as her son. Find Rex's age if his father is two years older than his mother.
3.Jason is now three times as old as Helston. Three years from now, Jason will be six times as old as Helston one year ago. Find their present ages.
4.Ten years from now, Michael will be twice his age ten years ago. How old is michael now?
5.Raymond is 6 years older than his sister. Four years from now, Raymond will be twice as old as his sister. Find their present ages.
Answer by Paul(988)   (Show Source):
You can put this solution on YOUR website! 1. Rewena's age = x-2
Gary's age = x
16 years before they were married:
Rewena = x-2-16
Gary = x-16
2(x-18)=x-16
2x-36=x-16
x=20
20-2=18
Hence Gary was 20 years old and Rowena was 18 years old.
2.
Rex's age = 3y+2-30
Mother's age = 3y
Father's age = 3y+2
Equation:
3y+2-30+3y=3y+2
6y-28=3y+2
3y=30
y=10
3(10)+2-30=2
3(10)=30
3(10)+2=32
Hence, Rex is 2 years old.
3.Helston's age= x
Jason's age = 3x
In three years Jason's age= 3x+3
Three years of Helston's age = x+3
One year ago Helston's age = x+1
Equation:
6(x+3-x+1)=3x+2
6(4)=3x+3
24=3x+3
3x=21
x=7
3(7)=21
Hence, Jason is 21 years old and Helston is 7 years old.
4. Micheal's current age = x
x+10=2(x-10)
x+10=2x-20
-x=-10
x=10
Hence, Micheal is 10 years old.
5.Sister's age = x
Raymond's age = x+6
Four years from now Raymond's age= x+6+4
Four years from now Sister's age = x+4
equation:
2(x+4)=x+10
2x+8=x+10
x=2
2+6=8
Hence, Raymond is 8 years old and his siter is 2 years old.
Paul.
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