SOLUTION: I am needing a refresher on word problems, its easy but i am unsure of myself 1. you and a friend take turns driving on a 450 mile trip. your friend drives for 3.5 hours at an a

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Question 286906: I am needing a refresher on word problems, its easy but i am unsure of myself
1. you and a friend take turns driving on a 450 mile trip. your friend drives for 3.5 hours at an average speed of 60 miles per hour. what must your average speed be for the remainder of the trip if you want to reach your hotel in 4 more hours?

Found 2 solutions by jim_thompson5910, ptaylor:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
If "your friend drives for 3.5 hours at an average speed of 60 miles per hour", then your friend has driven D=rt=60%2A3.5=210 miles. So you need to drive 450-210=240 more miles to complete the trip.


Now using D=rt, plug in D=240 (the amount of distance you need to cover) and t=4 (the amount of time you want to travel) to get 240=r%2A4. Divide both sides by 4 to get 240%2F4=r and reduce to get r=60

So you need to average 60 mph.

Answer by ptaylor(2198) About Me  (Show Source):
You can put this solution on YOUR website!
Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r
In 3.5 hours your friend has driven 3.5*60=210 mi leaving 450-210=240 for you to drive If you want to reach your hotel in 4 mores hours, your rate (or average speed) must be 240/4=60mph
So 7.5 hours at an average speed of 60 mph=450 mi
Hope this helps---ptaylor