SOLUTION: One pump can fill a gasoline tank in 10 hours. With a second pump working simultaneously, the tank can be filled in 6.5 hours. How long would it take the second pump to fill the ta
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-> SOLUTION: One pump can fill a gasoline tank in 10 hours. With a second pump working simultaneously, the tank can be filled in 6.5 hours. How long would it take the second pump to fill the ta
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Question 286799: One pump can fill a gasoline tank in 10 hours. With a second pump working simultaneously, the tank can be filled in 6.5 hours. How long would it take the second pump to fill the tank operating alone. Found 2 solutions by nyc_function, richwmiller:Answer by nyc_function(2741) (Show Source):
You can put this solution on YOUR website! First pump = 1/10
Second pump = 1/x
Together = 6.5
NOTE: 6.5 can be written as a fraction 13/2
Here is your equation:
1/10 + 1/x = 13/2
Can you find x now?
You can put this solution on YOUR website! Another approach is
6.5/10+6.5/x=1
6.5/x=3.5/10
65=3.5x
650=35x
650/35=x
65*5*2/5*7=x
65*2/7=x
130/7=x
x=18 4/7 hours
the first pump does 65% of the job and the second does 35%
