SOLUTION: A stats practitioner wishes to test the following hypothesis H0:μ = 600 against H1:μ<600. A sample of 50 observations yielded the statistics: mean = 585 and standard devi
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Question 286770: A stats practitioner wishes to test the following hypothesis H0:μ = 600 against H1:μ<600. A sample of 50 observations yielded the statistics: mean = 585 and standard deviation = 45. The test statistic of a test to determine there is enough evidence at the 10% signigicance level to reject the null hypothesis is? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A stats practitioner wishes to test the following hypothesis
H0:μ = 600 against
H1:μ<600.
A sample of 50 observations yielded the statistics: mean = 585 and standard deviation = 45. The test statistic of a test to determine there is enough evidence at the 10% signigicance level to reject the null hypothesis is?
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t(585) = (585-600)/[45/sqrt(50)] = -2.3570
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Cheers,
Stan H.
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