SOLUTION: h=-16t+vt+s A ball is tossed into the air from a height of 10 feet with an initial velocity of 12 feet /sec. Find the time t(in seconds) for the object to reach the ground.
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-> SOLUTION: h=-16t+vt+s A ball is tossed into the air from a height of 10 feet with an initial velocity of 12 feet /sec. Find the time t(in seconds) for the object to reach the ground.
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Question 286715: h=-16t+vt+s A ball is tossed into the air from a height of 10 feet with an initial velocity of 12 feet /sec. Find the time t(in seconds) for the object to reach the ground.
#2 a baseball player releases a baseball at a height of 6 feet with an initial velocity of 46 feet/sec. find the time(in seconds) for the ball to reach the ground.
You can put this solution on YOUR website! h=-16t+vt+s A ball is tossed into the air from a height of 10 feet with an initial velocity of 12 feet /sec. Find the time t(in seconds) for the object to reach the ground.
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h(t) = -16t^2 + 12t + 10
Solve: -16t^2 + 12t + 10 = 0
Modify: -8t^2 + 6t + 5 = 0
-8t^2 + 10t - 4t + 5 = 0
-2t(4t-5)-(4t-5) = 0
(4t-5)(-2t-1) = 0
Positive solution:
t = 5/4 second
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#2 a baseball player releases a baseball at a height of 6 feet with an initial velocity of 46 feet/sec. find the time(in seconds) for the ball to reach the ground.
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Solve:: -16t^2 + 46t + 6 = 0
8t^2 - 23t -3 = 0
8t^2 - 24t + t - 3 = 0
8t(t-3) + t-3 = 0
(t-3)(8t+1) = 0
Positive solution:
t = 3 seconds
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Cheers,
Stan H.
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