SOLUTION: find three consecutive odd positive intergers such that 2 times the sum of all three is 153 less then the product of the first and second intergers

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Question 286002: find three consecutive odd positive intergers such that 2 times the sum of all three is 153 less then the product of the first and second intergers
Answer by solver91311(24713) About Me  (Show Source):
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Let represent the smallest of the three integers. Then then next odd integer must be , and the one after that has to be

The sum of the three is



Two times the sum is then:



The product of the first and second is:



So, putting it all together:



Standard form:



Solve the factorable quadratic. Exclude the negative root because the problem asks for positive integers.

John