SOLUTION: x-7/ (x-4)^2 * x^2-3x -28/(x-7)^2

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Question 285906: x-7/ (x-4)^2 * x^2-3x -28/(x-7)^2
Answer by user_dude2008(1862) About Me  (Show Source):
You can put this solution on YOUR website!
[(x-7)/(x-4)^2] * [(x^2-3x-28)/(x-7)^2]

[(x-7)/(x-4)(x-4)] * [(x-7)(x+4)/(x-7)(x-7)]

[1/(x-4)(x-4)] * (x+4)


Answer: [(x-7)/(x-4)^2] * [(x^2-3x-28)/(x-7)^2] = (x+4)/(x^2-8x+16)