SOLUTION: log3(3x)=log3x+log3(4-x)

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Question 285871: log3(3x)=log3x+log3(4-x)
Answer by user_dude2008(1862) About Me  (Show Source):
You can put this solution on YOUR website!
log3(3x)=log3x+log3(4-x)


log3(3x)=log3[x(4-x)]

3x=x(4-x)

3x=4x-x^2

x^2-4x+3x=0

x^2-x=0

x(x-1)=0

x=0 or x-1=0

x=0 or x=1

Answer: only solution is x=1