SOLUTION: I need to find what X equals for: log(x-3)=(logx-log2) A)5/2 B)3+Square root 11)/2 c)6 D(2,11)

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: I need to find what X equals for: log(x-3)=(logx-log2) A)5/2 B)3+Square root 11)/2 c)6 D(2,11)      Log On


   

Question 285563: I need to find what X equals for: log(x-3)=(logx-log2)
A)5/2
B)3+Square root 11)/2
c)6
D(2,11)
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The general rule is:
log%28a%29+-+log%28b%29+=+log%28a%2Fb%29, so
log%28x-3%29+=+log%28x%29+-+log%282%29
log%28x-3%29+=+log%28x%2F2%29
If the logs are equal, the quantities are equal
x+-+3+=+x%2F2
2x+-+6+=+x
x+=+6
The answer is (C)