Question 285519: What is the conjugate of (a+ib)/(a-ib)?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! What is the conjugate of (a+ib)/(a-ib)?
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(a+bi)/(a-bi)
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Multiply numerator and denominator by (a+bi)
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= (a+bi)^2/(a^2+b^2)
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= [(a^2-b^2) + 2abi)/(a^2+b^2)
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The conjugate is:
[[(a^2-b^2) - 2abi)/(a^2+b^2)
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cheers,
Stan H.
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