Question 285511: How many different ways are there for an admissions officer to select a group of 8 college candidates from a group of 12 applicants for an interview?
and
Which pair has equally likely outcomes? List the letters of the two choices below which have equal probabilities of success, separated by a comma.
A. rolling a total of 4 on two fair six sided dice
total possible combinations = 3 (1,3 and 3,1 and 2,2)
total sample size is ???
3 / ???
B. drawing a black seven out of a standard 52 card deck given it’s not a face card or an ace.
2 / (52-16) = 2/36 = 1/18
C. rolling a total of 11 on two fair six sided dice ??
D. rolling a total of 7 on two fair six sided dice ??
E. drawing a three out of a standard 52 card deck given it’s not a face card or an ace.
3 / (52-16) = 3/39 = 1/13
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! How many different ways are there for an admissions officer to select a group of 8 college candidates from a group of 12 applicants for an interview?
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12C8 = 12C4 = (12*11*10*9)/(1*2*3*4) = 3*11*5*3 = 45*11 = 495 ways
and
Which pair has equally likely outcomes? List the letters of the two choices below which have equal probabilities of success, separated by a comma.
A. rolling a total of 4 on two fair six sided dice
total possible combinations = 3 (1,3 and 3,1 and 2,2)
total sample size is ???
3 /36 = 1/12
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B. drawing a black seven out of a standard 52 card deck given it’s not a face card or an ace.
Ans: 2 / (52-16) = 2/36 = 1/18
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C. rolling a total of 11 on two fair six sided dice
Ans: 2/36 = 1/18
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D. rolling a total of 7 on two fair six sided dice
Ans: 6/26 = 1/6
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E. drawing a three out of a standard 52 card deck given it’s not a face card or an ace.
Ans: 4 / (52-16) = 4/39
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Cheers,
Stan H.
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