SOLUTION: Solve 2log4-log3+2logx=4

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Question 285468: Solve 2log4-log3+2logx=4
Answer by edjones(8007) About Me  (Show Source):
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2log4-log3+2logx=4
log(16)-log(3)+log(x^2)=4
10^(log(16))/10^(log(3))*10^(log(x^2))=10^4
16x^2/3=10000
16x^2=30000
x^2=1875
x=sqrt(625*3)
=25sqrt(3)
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Ed