SOLUTION: Area of a painting. A rectangular painting with a width of
x centimeters has an area of x2 + 50x square centimeters.
Find a binomial that represents the length.
So what I have
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Polynomials-and-rational-expressions
-> SOLUTION: Area of a painting. A rectangular painting with a width of
x centimeters has an area of x2 + 50x square centimeters.
Find a binomial that represents the length.
So what I have
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Question 285446: Area of a painting. A rectangular painting with a width of
x centimeters has an area of x2 + 50x square centimeters.
Find a binomial that represents the length.
So what I have is that:
A=lxwxh
w=x
In this problem:
A=x^2 + 50x^2
I am guessing the following:
LxXxH=x^2+50x^2
You can put this solution on YOUR website! Area of a painting. A rectangular painting with a width of
x centimeters has an area of x2 + 50x square centimeters.
Find a binomial that represents the length.
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Area = width*length
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Substitute and solve for "length":
x^2+50x = x(length)
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length = (x^2+50x)/x
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length = x + 50
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Cheers,
Stan H.
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