SOLUTION: write an equation of the line containing the given point and perpendicular to the given line, Express your answer in the form y=mx+b
(3,7);7x+y=8
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-> SOLUTION: write an equation of the line containing the given point and perpendicular to the given line, Express your answer in the form y=mx+b
(3,7);7x+y=8
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Question 285404: write an equation of the line containing the given point and perpendicular to the given line, Express your answer in the form y=mx+b
(3,7);7x+y=8 Found 2 solutions by richwmiller, stanbon:Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website! slope is -a/b =-7/1=-7
perpendicular slope is 1/7
7=3/7+b
49=3+7b
46=7b
46/7=b
y=x/7+46/7 slope intercept form
7y=x+46
check
7=3/7+46/7
49=3+46
ok
You can put this solution on YOUR website! write an equation of the line containing the given point and perpendicular to the given line, Express your answer in the form y=mx+b
(3,7);7x+y=8
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Find the slope of the given line:
y = -7x+8
slope = -7
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The slope of any line perpendicular to the
given line is 1/7
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Find Equation of line with slope = 1/7 and passing thru (3,7)
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7 = (1/7)3 + b
49/7 = 3/7 + b
b = 46/7
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Equation:
y = (1/7)x+(46/7)
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Cheers,
Stan H.
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