SOLUTION: a quadrilateral with angles that mesure: 10x-25, 10x, 3x to the second power, and 2x to the second power. solve for x.
Algebra ->
Polygons
-> SOLUTION: a quadrilateral with angles that mesure: 10x-25, 10x, 3x to the second power, and 2x to the second power. solve for x.
Log On
You can put this solution on YOUR website! a quadrilateral with angles that mesure: 10x-25, 10x, 3x to the second power, and 2x to the second power. solve for x.
SUM OF 4 ANGLES IN A QUADRILATERAL =360 DEGREES...SO...
10X-25+10X+3X^2+2X^2=360
5X^2+20X-385=0...DIVIDING WITH 5 WE GET...
X^2+4X-77=0
X^2+11X-7X-77=0
X(X+11)-7(X+11)=0
(X+11)(X-7)=0
X=7 OR -11..SINCE -11 IS NOT TENABLE X=7
