SOLUTION: I could really use your help today, I am stuck.
x/x-2=1/2-x+2/x
2x(x)/2x(x-2)=x(x-2)/2x(x-2)-2(x-2)(x+2)/2x(x-2)
2x^2/2x(x-2)=x^2-2x/2x(x-2)-x^2+8/2x(x-2)
I am lost from h
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: I could really use your help today, I am stuck.
x/x-2=1/2-x+2/x
2x(x)/2x(x-2)=x(x-2)/2x(x-2)-2(x-2)(x+2)/2x(x-2)
2x^2/2x(x-2)=x^2-2x/2x(x-2)-x^2+8/2x(x-2)
I am lost from h
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Question 285289: I could really use your help today, I am stuck.
x/x-2=1/2-x+2/x
2x(x)/2x(x-2)=x(x-2)/2x(x-2)-2(x-2)(x+2)/2x(x-2)
2x^2/2x(x-2)=x^2-2x/2x(x-2)-x^2+8/2x(x-2)
I am lost from here as the last term numerator is negative. I must have made a wrong turn along the way. I appreciate your help.
Thank you,
Tina Answer by user_dude2008(1862) (Show Source):
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