SOLUTION: Solve. Where appropriate, include approximations to four decimal places. An investment with interest compounded continuously doubled itself in 16 yr. What is the interest rate?

Algebra ->  Rational-functions -> SOLUTION: Solve. Where appropriate, include approximations to four decimal places. An investment with interest compounded continuously doubled itself in 16 yr. What is the interest rate?       Log On


   



Question 285204: Solve. Where appropriate, include approximations to four decimal places.
An investment with interest compounded continuously doubled itself in 16 yr. What is the interest rate?
Can someone please help me?

Found 2 solutions by rfer, MathTherapy:
Answer by rfer(16322) About Me  (Show Source):
Answer by MathTherapy(10555) About Me  (Show Source):
You can put this solution on YOUR website!
This is future value, and the formula for future value, with continuous compounding is: A+=+Pe%5E%28rt%29, where A = future value, P = present value, e = continuous compounding factor, or 2.7182818, r = annual interest rate, and t = time, in years = 16.

Let P = P. Then A = 2P, since the initial investment doubled.
A+=+Pe%5E%28rt%29 would then give us:
2P+=+P%282.7182818%29%5E%2816r%29
2+=+2.7182818%5E%2816r%29 ---------- Dividing by LCD P
We can rewrite this as 2.7182818%5E%2816r%29+=+2

Applying logs, we get: = log+2.7182818%5E%2816r%29+=+log+2

16r+log+2.7182818+=+log+2
16r+=+%28log+2%29%2Flog+2.7182818
16r+=+0.693147
r+=+0.693147%2F16+=+0.043322, or 4.3322%
Therefore, the rate at which an investment doubles in 16 years, with continuous compounding interest is: highlight_green%284.3322%29%.