SOLUTION: A height of 96 feet at an initial velocity of 80 feet per second, then its height h after t seconds is given by the equation H=16t^2+ 80t + 96.After how many seconds does the objec
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-> SOLUTION: A height of 96 feet at an initial velocity of 80 feet per second, then its height h after t seconds is given by the equation H=16t^2+ 80t + 96.After how many seconds does the objec
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Question 285029: A height of 96 feet at an initial velocity of 80 feet per second, then its height h after t seconds is given by the equation H=16t^2+ 80t + 96.After how many seconds does the object hit the ground? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! H=16t^2+ 80t + 96
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As t increases, H will increase as a function of the square of t. It will never hit the ground.
