SOLUTION: (4,0)(0,2) points on the line . 1.Find y when x=6 2. Find x when y=-1 3. Find the x-intercept 4. Find the slope of the line 5. Find the equation of the line. 6. Find

Algebra ->  Linear-equations -> SOLUTION: (4,0)(0,2) points on the line . 1.Find y when x=6 2. Find x when y=-1 3. Find the x-intercept 4. Find the slope of the line 5. Find the equation of the line. 6. Find      Log On


   



Question 285008: (4,0)(0,2) points on the line .


1.Find y when x=6
2. Find x when y=-1
3. Find the x-intercept
4. Find the slope of the line
5. Find the equation of the line.
6. Find y when x =-2
7. find x when y = -5
8. Find the y intercept.

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!

Plot the points:



Draw the line:




1.Find y when x=6

Draw a vertical line through 6 on the x-axis



From where the blue line crosses the green line draw a red horizontal 
line



Look and see that the red horizontal line crosses the y-axis at -1.

So the answer is y = -1 when x = 6.

2. Find x when y=-1

We just got through showing that "when x = 6, y = -1".  So just
turn that around and say "when y = -1, x = 6


3. Find the x-intercept.

We look and see where the green line crosses the x-axis.



We see it is one of the points we were given at the start.  It is the point
(4,0) 

The x-intercept is the point (4,0).

4. Find the slope of the line

We draw a horizontal blue line from the given point (0,2) rightward until
we are directly above the other given point (4,0) and then draw a
vertical red line from there down to the point (4,0), like this:




The horizontal blue line is 4 units long and goes right, so we assign it
the value +4.  (If it had gone left we would have assigned it -4).  The 
vertical line is 2 units long and goes down, so we assign it the value -2.
(If it had gone up we would have assigned it the value +2).

         vertical line's value       -2 
Slope = ------------------------- = ----- = %28-2%29%2F4=-1%2F2
         horizontal line's value     +4



5. Find the equation of the line.

y-y%5B1%5D=m%28x-x%5B1%5D%29

Substitute the slope -1%2F2 for m. 
Since the green line goes through (4,0), substitute 4 for x%5B1%5D
and 0 for y%5B1%5D.  Leave x and y as they are:

y-0=%28-1%2F2%29%28x-4%29

Then simplify:

y=%28-1%2F2%29x%2B2

6. Find y when x =-2

Two ways.

First way.  

---

1.Find y when x=-2

Draw a vertical line through -2 on the x-axis



From where the blue line crosses the green line draw a red horizontal 
line



Look and see that the red horizontal line crosses the y-axis at 3.

So the answer is y = 3 when x = -2.

Second way:

Substitute -2 for x in the equation we found in 5

y=%28-1%2F2%29x%2B2
y=%28-1%2F2%29%28-2%29%2B2
y=1%2B2
y=3

7. find x when y = -5

Two ways:

First way:

Draw a horizontal line through -5 on the y-axis:



Oh my! we have to make the graph wider so the red line will cross
the green line:



From where the red line crosses the green line we draw a blue vertical 
line



Look and see that the blue vertical line crosses the x-axis at 14.

So the answer is x = 14 when y = -5.

Second way:

Substitute -5 for y in the equation we found in 5:

y=%28-1%2F2%29x%2B2
-5=%28-1%2F2%29x%2B2
Multiply both sides by 2
-10=-x%2B4
-14=-x
x=14

8. Find the y intercept.

First way:

We look and see where the green line crosses the y-axis.



We see it is one of the points we were given at the start.  It is the point
(0,2) 

The y-intercept is the point (0,2).

Second way:

Substitute x=0 in the equation we found in 5:

y=%28-1%2F2%29x%2B2
y=%28-1%2F2%29%280%29%2B2
y=0%2B2
y=2

So we substituted x=0 and got y=2 so the y-intercept is (0,2).

Edwin