SOLUTION: One root of x^4-x^3-7x^2+x+6 is x=-1 What is another root?
-1] 1 -1 -7 1 6
-1 +2 +5 -6
___________ ______
1 -2 -5 6 0
x^3-2x^2-5x+6
I am lost from this
Algebra ->
Rational-functions
-> SOLUTION: One root of x^4-x^3-7x^2+x+6 is x=-1 What is another root?
-1] 1 -1 -7 1 6
-1 +2 +5 -6
___________ ______
1 -2 -5 6 0
x^3-2x^2-5x+6
I am lost from this
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Question 284836: One root of x^4-x^3-7x^2+x+6 is x=-1 What is another root?
-1] 1 -1 -7 1 6
-1 +2 +5 -6
__________________
1 -2 -5 6 0
x^3-2x^2-5x+6
I am lost from this point, do I factor by using grouping then find the additional roots?
Thank you for your help I appreciate it very much.
Tina
You can put this solution on YOUR website! x=1 is also a root.
I plugged it into the original and in your second equation.
You can then divide your second equation by (x-1) to get to the quadratic.
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You can then check your solution by going to www.1728.com/cubic.htm.
