SOLUTION: A truck can be rented from company A for 70.00 per day and .20 cents per mile. Company B charges 50.00 per day and .60 cents per mile. How many miles must be driven in a day for co

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: A truck can be rented from company A for 70.00 per day and .20 cents per mile. Company B charges 50.00 per day and .60 cents per mile. How many miles must be driven in a day for co      Log On


   

Question 284750: A truck can be rented from company A for 70.00 per day and .20 cents per mile. Company B charges 50.00 per day and .60 cents per mile. How many miles must be driven in a day for company A to be a better deal than company B?
Found 3 solutions by Fombitz, checkley77, richwmiller:
Answer by Fombitz(32388) About Me  (Show Source):
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You want to know when the cost from Company A exceeds the cost from Company B.
For A,
C=70%2B0.2%2AM
For B,
C=50%2B0.6%2AM
Find M when,
70%2B0.2%2AM%3E50%2B0.6%2AM
20%3E0.4M
M%3C100
So you must drive less than 100 miles in 1 day for Company A to be a better deal than Company B.

Answer by checkley77(12844) About Me  (Show Source):
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70+.20D<=50+.60D
.20D-.60D<=50-70
-.40D<=-20
D>=-20/-.40 NOTE THE SIGN CHANGE DUE TO DIVIDING BY A NEGATIVE VALUE.
D>=50 MILES WILL MAKE THE 2 COMPANIES EQUAL.

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
I see the other tutors don't agree.
a=70+.2m
b=50+.6m
set them equal
70+.2m=50+.6m
20=.4m
multiply by 10
200=4m
200/4=50 the break even point is 50 miles
after that a is the better deal