SOLUTION: the line passes thru (4,-7) and is perpendicular to the line whose equation is x-2y=3 write an equation in slope intercept form satisfying the given conditions

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Question 284715: the line passes thru (4,-7) and is perpendicular to the line whose equation is x-2y=3
write an equation in slope intercept form satisfying the given conditions
Answer by eggsarecool(46) About Me  (Show Source):
You can put this solution on YOUR website!
The first step in such a problem is to solve the given equation for y.
x-2y=3 So subtract x from both sides.
-2y=3-x Now divdie everything by -2.
y=-3%2F2+%2B+%281%2F2%29%2Ax The number attached to the x is the slope of this line, 1%2F2 To get a line that is perpendicular you need to take the negative reciprocal which would be -2%2F1 or just -2.
We now do y=mx%2Bb m stands for slope so we have.
y=-2x%2Bb Now you plug in (4,-7), 4 for x and -7 for y to get the line that passes through that point and solve for b.
-7=-2%2A4%2Bb
-7=-8%2Bb add 8 to both sides.
1=b
Going back to y=-2x%2Bb you will now put in the b you found.
And y=-2x%2B1 is your final answer.