Question 284674: find three consecutive intergers such that the sum of three times the middle integer and five times the smaller integer is the same as seven times the larger integer
Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! let the integers be x , x+1, x+2
3times the middle = 3(x+1)
5times the smaller =5x
7 times the largest = 7(x+2)
3(x+1)+5x=7(x+2)
3x+3+5x=7x+14
8x+3=7x+14
8x-7x=14-3
x=11
the numbers are 11 , 12, 13
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