Question 284562: Four times the sum of three consecutive integers is 48
a. Write an equation that could be used to find the integers
b. What are the integers Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! The integers can be:
n, n+1 and n+2
4*(n + n+1 + n+2) = 48
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Using the equation is the hard way. Do it like this:
The integers total 12
12/3 = 4, the middle number
--> 3, 4 & 5
