SOLUTION: The perimeter of a rectangle is to be no greater than 300 in., and the length must be 125 in. Write an appropriate inequality, then find the maximum width of the rectangle.
300
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300
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Question 28442: The perimeter of a rectangle is to be no greater than 300 in., and the length must be 125 in. Write an appropriate inequality, then find the maximum width of the rectangle.
300>250+2W
I'm lost am I doing this right. Found 2 solutions by elima, josmiceli:Answer by elima(1433) (Show Source):
You can put this solution on YOUR website! Yes your doing a great job! Now is all you need to do is find w.
300>250+2w
subtract 250 from both sides;
300-250>2w
50>2w
Now divide each side by 2; >
25>w
=)
You can put this solution on YOUR website! It's almost right
"no greater than" is another way of saying "less than or equal to"
the perimeter = 2l + 2w
2l + 2w <= 300
w = 125
2l + 2(125) <= 300
2l + 250 <= 300 (this is close to what you got)
subtract 250 from both sides
2l <= 50
l <= 25
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