SOLUTION: The area of a square exceeds the area of a rectangle by 4 square inches. The width of a rectangle is 5 inches and the length is 4 inches longer than the side of the square. Find th

Algebra ->  Rectangles -> SOLUTION: The area of a square exceeds the area of a rectangle by 4 square inches. The width of a rectangle is 5 inches and the length is 4 inches longer than the side of the square. Find th      Log On


   

Question 284331: The area of a square exceeds the area of a rectangle by 4 square inches. The width of a rectangle is 5 inches and the length is 4 inches longer than the side of the square. Find the side of the square.
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
s^2=L*w+4
w=5
L=s+4
L = 12, s = 8, w = 5
check
64=(5*12)+4
L=8+4
ok