SOLUTION: Im having trouble understanding this one could you explain how to get the answer please?: A rectangle has area of x^2+3x-18 and width x-3 find the factor for the length

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Im having trouble understanding this one could you explain how to get the answer please?: A rectangle has area of x^2+3x-18 and width x-3 find the factor for the length      Log On


   



Question 284109: Im having trouble understanding this one could you explain how to get the answer please?:
A rectangle has area of x^2+3x-18 and width x-3 find the factor for the length

Found 2 solutions by richwmiller, oberobic:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
You either have to factor x^2+3x-18 into (x-3) and something else or you have to divide x^2+3x-18 by (x-3)
Since we have -18 (-3*6=-18) I would guess (x+6) is the other factor.
Use foil to multiply (x-3)*(x+6) to verify.

Answer by oberobic(2304) About Me  (Show Source):
You can put this solution on YOUR website!
A+=+area+=+Length++%2A+Width
.
A+=+x%5E2+%2B+3x+-18
.
W+=+width+=+x-3
.
Since
A+=+L%2AW
We can rearrange to say that
A%2FW+=+L,
which suggests you divide A/W (that is, polynomial division).
.
But you may be able to factor the equation to advantage.
.
x%5E2+%2B+3x+-18+=+%28x%2B6%29%28x-3%29
.
So substituting what we know
.
A+=+L+%2A+W
A+=+%28x%2B6%29+%2A+W
.
Which means
L+=+%28x%2B6%29
.
Done