SOLUTION: I need help with this one homework question.
A ball is thrown into the air with an initial upward velocity of 60ft/sec. Its height (h) in feet after 1 sec is given by the functio
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-> SOLUTION: I need help with this one homework question.
A ball is thrown into the air with an initial upward velocity of 60ft/sec. Its height (h) in feet after 1 sec is given by the functio
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Question 284087: I need help with this one homework question.
A ball is thrown into the air with an initial upward velocity of 60ft/sec. Its height (h) in feet after 1 sec is given by the function h=-16t2(2= squared cant make a little 2)+60t +6
a: after how many seconds will the ball hit the ground?
b: what will the height be at if t= 3 seconds
i think for part be the answer is 42 ive plugged in 3 for t and got 42 i have no idea how to get part A Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! A ball is thrown into the air with an initial upward velocity of 60ft/sec. Its height (h) in feet after 1 sec is given by the function h=-16t2(2= squared cant make a little 2)+60t +6
Not for 1 second, but at t seconds
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a: after how many seconds will the ball hit the ground?
It hits the ground when h(t) = 0
Quadratic equation (in our case ) has the following solutons:
For these solutions to exist, the discriminant should not be a negative number.
First, we need to compute the discriminant : .
Discriminant d=996 is greater than zero. That means that there are two solutions: .
Quadratic expression can be factored:
Again, the answer is: -0.0974667297574374, 3.84746672975744.
Here's your graph:
Use the + value, ~3.847 seconds
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b: what will the height be at if t= 3 seconds
h(3) = -16*9 + 60*3 + 6 = -144 + 180 + 6
h(3) = 42 feet
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i think for part be the answer is 42 ive plugged in 3 for t and got 42 i have no idea how to get part A