SOLUTION: A container has 6 blue marbles, 2 red marbles, and 3 green marbles. If 3 marbles are drawn with replacement, what is the probability that all three will be blue?

Algebra ->  Probability-and-statistics -> SOLUTION: A container has 6 blue marbles, 2 red marbles, and 3 green marbles. If 3 marbles are drawn with replacement, what is the probability that all three will be blue?      Log On


   



Question 283904: A container has 6 blue marbles, 2 red marbles, and 3 green marbles. If 3 marbles are drawn with replacement, what is the probability that all three will be blue?
Found 2 solutions by richwmiller, brucewill:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
there are 6+2+3 marbles 11 total 6/11 are blue
(6/11)^3=216/1331=16.23%

Answer by brucewill(101) About Me  (Show Source):
You can put this solution on YOUR website!
"With Replacement" means the probability is the same for each attempt. So, essentially, you are asking what is the probability of blue AND blue AND blue.
Probability of blue: 6/11.
Three blue in a row: %286%2F11%29+%2A+%286%2F11%29+%2A+%286%2F11%29+=+highlight%28216%2F1331%29+or+16.228%25