You can put this solution on YOUR website! let one integer be x
four times integer = 4x
4x-5 is the second number
x(4x-5)=21
4x^2-5x-21=0
4x^2-12x+7x-21=0
4x(x-3)+7(x-3)=0
(x-3)(4x+7)=0
SO x= 3 or -7/4
but the integer is positive so x=3
the other number = 12