SOLUTION: Express as a sum of logarithms. log[4](64 ∙ 256)

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Question 283763: Express as a sum of logarithms.
log[4](64 ∙ 256)

Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
In algebgra.com language, the answer is:

log(4,(64*256)) = log(4,64) + log(4,256)

After being put through the algebra.com formula generator, the answer looks like this:

log%284%2C%2864%2A256%29%29+=+log%284%2C64%29+%2B+log%284%2C256%29

In english, the answer is:

log(64*256) to the base of 4 is equal to log(64) to the base of 4 plus log(256) to the base of 4.

In your language, the answer is:

log[4](64*256) = log[4](64) + log[4](256).

This is because, in general:

log(b,a*c) = log(b,a) + log(b,c)