SOLUTION: I'm trying to factor a problem and I really don't know where to start. The problem is dk + 3dm − 2ek − 6em. If someone could help me with this and maybe give me some

Algebra ->  Distributive-associative-commutative-properties -> SOLUTION: I'm trying to factor a problem and I really don't know where to start. The problem is dk + 3dm − 2ek − 6em. If someone could help me with this and maybe give me some       Log On


   

Question 283683: I'm trying to factor a problem and I really don't know where to start. The problem is dk + 3dm − 2ek − 6em. If someone could help me with this and maybe give me some suggestions on how to solve problems like this in the future I would be extremely grateful.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
dk%2B3dm-2ek-6em Start with the given expression.


%28dk%2B3dm%29%2B%28-2ek-6em%29 Group the terms into two pairs of groups


d%28k%2B3m%29%2B%28-2ek-6em%29 Factor out the GCF 'd' from the first group.


d%28k%2B3m%29-2e%28k%2B3m%29 Factor out the GCF '-2e' from the second group.


%28d-2e%29%28k%2B3m%29 Factor out the GCF k%2B3m from the entire expression.


So dk%2B3dm-2ek-6em factors to %28d-2e%29%28k%2B3m%29


In other words, dk%2B3dm-2ek-6em=%28d-2e%29%28k%2B3m%29